my eqn of locus is coming his (x-1)^2/4 +y^2/3=1??
Please send the working
Is it B,D
Let centre be (h,k).
- distance of (h,k) from (0,0) = 5-(radius of circle ®)
- Distance of (h,k) from (2,0) = r+1
I’m getting (x-1)²/9 + y²/8 =1
@Sarvesh_Pnchl please try the other problems as well
Dono Q ka sense samjha do fixed pt ke abt rotate karne ke do pts h toh confuse ho raha hu please try @mihir @Cooljet123 @complexroots @harsh2 @Aswin24 @Seshank and @others anyone please try this…
For Q.no 5 take a point (x,y) and find the slopes of the line connecting the point (x,y) and the given points…( call them tan θ1 and tan θ2 ) … as per the given info, d( θ1)/dt = 2 d( θ2)/dt or θ1=2 θ2 …
So arctan(m1) = 2 arctan(m2) Sub in the m1 and m2 values and use 2 arctan expansion formula and equate the insider terms of LHS and RHS which gives partial circle eq ig
What abt 1st Q!??
@Karan_Ralhan I am not even able to understand bro, reading again and again…
Same issue… With me