Doubt from maths


@KrishSharma @Binod @Cooljet123 and anyone

1 Like

Bro take one zero I guess, suppose x=0. Then y will be =z^11/4. There exist infintely many values of z(integers) in the form of n^4 so there will be infinite solutions.

Other than this koyi idea nahi aya.

2 Likes

What’s the solution given, if any?

No bro its not given

1 Like

Let x = 0 => y4 = z11 => y = z11/4 (many values of z of the form (integer)4 will give integral values of y. so infinite sets. Similarly take y=0 and z=0 also u will get infinetely more.

I guess its a rmo problem

3 Likes

I too said the same but you got solution…:frowning:

1 Like

Bhai i got confused ki kisko solution ka tag du dono sahi h .

2 Likes

Lol I was just joking man, hehe. I dont mind

2 Likes

bhai agar bura nahi mane ho toh yeh bhi batado please

2 Likes

Is answer 11? Tell bro, did lot of hardwork.

1 Like

See this

1 Like

115900 right?

1 Like

Yes. Exactly what I did, but I used calculator also. Lol. To cross check.

Bhai aajtak tumhara koi ans galat hua h kya, Hamesha sahi hi rehta h bhai

1 Like

Bhai solution ka tag dede😅

1 Like

Lol, I always check bro, that’s why itna time ke bad reply kiya without method and steps also. Par exams me Sara galat I’ll do lol.

Bro yeh first line samjhado kaise convert kiye?

1 Like

Ignore first line, that was rough work

1 Like

Nice bro!

1 Like

Bhai vo pehli line jisme tumne x= 1. (\ 2^{3} -1) +2(\ 3^{3}- \ 2^{3} ) karke likha h ye kaise laaye bas samjhado