That salt hydrolysis formula right? Yeah you can.

For question 8 use van der Waals equation bro. Just put b=0 as they said that volume occupied by CO2 is negligible.

So bro( P + an^2 \over V^2) (V-n b ) = n R T

Now putting n =1 and b=0 i get

(P + a \over V^2 ) V = R T

Now in the given question i have to find P but so a ,V, T should be known but only a and T are given please help @Rudra_d

Hm didn’t notice that. I have an exam today. Will try after that.

Ok bro

@Achyut_Singh dekho jo tum bol rahe woh sahi hai

Uske aage mai batata hu

Dekho v me quadratic banao kuki 1 particular value of t and p be 1 hi value aayega v ka to jo tum quadratic banaoge uska discriminant 0 kar dena

.ans dikh jayega

Dhanywaad

Apka din magalmay ho🙃

Equal roots me kya lagate ho

Toh tumhe kaise pata hai ki yaha par equal roots ki condition lagegi ? Mujhe kuch samjh nhi aa rha h ek bar samjhado please

Koi 1 temp aur pressure ki condition par 1hi value na aaygi volume ki aur quadratic hamlog 2 value de dega

Par dono value 1 hi honi chahiye na isliye equal roots jaisa condition hoga to hamlog D=0 Istamal kardenge

Baad me dekhenge abhi kaam hai thora

is the answer to que no.4 is four ?

At first equivalence point, NaHCO3 will be present which is an amphiprotic species.

Use pH= (pka1 + pka2)/2 to get pH1 which will be 6.3

At II equivalence point which is the end point of titration there will only be Na2CO3 which will cause hydrolysis in 2 steps but 2nd step hydolysis will be negligible.

[CO3]2- will come as 0.04 M or 1/25 M by balancing the equivalents. then calculate first hydrolysis constant. use Kh1=Kw/Ka2 it will come 10^-6.

Find [OH-] and pOH. So pH2 comes out to be 10.3

this will give (pH2-pH1) = 4

Plz confirm

Yes it is the correct answer, I checked from the key just now

okay bro

bro write as

C_6H_6 + 3H_2 -> C_6 H_12

x y –

- y -3x x

earlier x + y = 60

then y - 2x = 30

solve it…

Bhai yeh line samjh nhi aayi