Doubt from physics


How to find induced emf when rod is
(i) conducting
(ii) non conducting
Please help @Rudra_d @LaveshGupta @Ishaan_Shrivastava @VenkatAmith and everyone

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Circle me ghum rahi hai rod?

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Haan

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To phir conducting me Bwl^2/2 aur non conducting me zero. Most probably.

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@Aastik_Guru ye bhi batado please


@VenkatAmith @LaveshGupta and anyone @Electric_arch

IMG-20200826-WA0014

@Karan_Ralhan and anyone please @Aswin24

Take an element and write force on it.Now take see that vertical component will add up and horizontal will cancel each other.
Force=pressure×area.Take an element at a distance from top.Integrate the expresseion from 0 to pi/2.Similarly solve for bottom part also.You will get a factor òf 1/6 in force on upper part and a factor of 5/6 on force in lower part.

Try it.If you don’t get the answer do tell me.I will post the written solution by tomorrow.

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Bina Integration bhi kar sakte hai ise. Tum solution de do pehle uske baad me bhejta hun.

Orally answer a jaayega

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Can someone give me his notes of Mean free path , collision frequency, relaxation time

I saw on you tube but it’s not helping me

@Aastik_Guru
@Aswin24
@others

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thik hai phir.
Bina integration ke bhi aa gya mera.


@Achyut_Singh

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Bhai ye vala bhi batado agar free ho toh

Aur yeh bhi

B hai ans

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Accha bhai thora samjhahi do ki kaise tum last vala soche ho ? Mujhe toh A lag rha tha
@Achilles

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I don;t have any logic :sweat_smile:
I just imagined a block of jelly kept on incline.
And visualized how it will feel like

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:joy: nice bro :ok_hand:t2:

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Aur bro vo frequency vala tumne try kiya ?

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600 hi aana chaiye mere hisab se bhi
Jab closest hoga
Toh velocity along line joining them zero hogi
So no change

btw which vedantu tests are these ??

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