Koi solve karo na mera pho rsquare/12episilon not aa raha hai

Ans D hai

@Cooljet123 @Naman1 @mihir @Aswin24 @Ishaan_Shrivastava @harsh2 bro aur jo bhi online hai

@Aastik_Guru jab aana to bana dena ye

Bro I am not able to follow your solution at all… Can you write the expression for electric field that you used, again? @Vibhu_Kumar

Like I can see a bunch of stuff that you might have used but there is a lot of rough calculation which is a bit confusing

I am getting this answer…

Dekho mai aise kiya ki A pe nikala bada wala aur sphere aur chota wala sphere dono ka madad se (bada-chota)

Same I used for B

Mai E=kq/r2 outside aur pr/3Eo andar jo formula hota hai uska istamal kiya

Electric field inside the sphere is KQr/R^3

Bro p me convert karega to wahi aayega Pr/3Eo

Okay. And using this, what values of absolute potential did you get for both A and B?

Oh Haan cooljet waala formula hi use karlo. But I am not able to understand the mistake you made, as long as you integrated properly

Yeah, got what you said. Use potential at a point inside solid charged sphere : \frac{KQ}{2R^3} (3R^2 -r^2)

Maine net change in electric field naikal aur fur v=e.dl ki madad se change in potential nikala jisme l =r/2 liya dono ke beech ka ( A -B)length

Ab samjaha do mara galat ku ho raha hai

@Ishaan_Shrivastava @Cooljet123

Integrate electric field directly from points R/2 to R. I don’t think you should subtract the fields…Because field is not constant.

Ok bro

Ah so you did ∆E.∆L.

This is wrong for the following reason:

Potential difference is the integral of -E.dl which simply doesn’t equate to what I wrote in first line of my comment.

Is the answer 5m?