# Probability doubts

I will be asking all my probability questions doubts here in this thread… Pls help me with them.
Peace.

(I m very weak in this topic )

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Enjoy
4th - C
5th- A
11th - A
12th - B
15th - Tum btao

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Noice questions, kal subah uthte hi try karunga agar kisi ne na kiye to

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Turu ig

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Reverse engineering…
Agar fly ko R pe aana h to
Wo B or W pe First land kregi yahi possible ways h taki wo R pe end kre
Now
B (1/6) AND W (1/6) but w pe ane k baad Right and left two ways jisme favourable h Right to W (1/6*1/2)

Probability → 1/6 + 1/6*1/2 = 1/6 + 1/12 = 1/4 A

Btw ye Allen k modules k sawal rag rag me base hue h

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Question smjh nhi aya shi se

Ans 13:5

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Ha allen ne bansal se copy mare honge

Thanks for solution

False h given

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Accha aisa tha… Mujhe lga vo multiple times udte udte R pe pahunch jayegi… Thanks for clearing the doubt

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Isme table bana k try Karo…
From 1 to 10 iske squares likho then sum of sq of two numbers unka unit digit 0 or 5 jin cases me ayega…
I hope ho jayega isse …

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Infinite arhe h like… I did by this…
a²+b²=5k, k €Z
Then k=1,2,4,5,8,9,10,13,17,…… Pe a aur b satisfy kre the eqn… Kha galat kiya h

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Sawal ajeeb lag rha
Usme wo Atleast two of them land same way nhi samjh aya…

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Mujhe last wali line me… “either the same way or oppositely” smjh nhi aya

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Are bro
1-> 1
2-> 4
3-> 9
4-> 6
5-> 5
6-> 6
7-> 9
8-> 4
9-> 1
10-> 0
Number → unit digit of Number²
Isme
Dekho kin kin ko add krne se 0 or 5 unit digit ayege
Ab this / 100 is ur answer

(1,4)(1,9)(1,9)(1,4)(4,6)(4,6)(4,1)… aese
Ye unit digit likhe h squared terms k upar se start krte krte jinka sum 0/5 aa rha

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@VasuBro samjhe??

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Koi question bacha ya @VictoryGod bhaiya ne sab uda diye?

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As the probabilities of heads or tails are both 1/2, as the number of tosses increase, the ratio of heads to tails will tend to get closer to 1/2, but it will never be exactly 1/2. For proof, you can take a coin and try this yourself .

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Accha. Aise krna tha…
Thanks budyy

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Ha bache h…
4,15,17

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S = 1-p
Infinite series banti h isme

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Iska matlab hai ki ek race me 6 horses hain, aur unme se ek horse A hai. B ya C me se koi ek banda, horse A par baith sakta hai. [P(B rides A)]/[P(C rides A)] = 2/1. If B rides A, all the horses have equal probability of winning, whereas if C rides A, C’s probability of winning becomes 3 times. Hame dhundna hai what are the odds against his (C’s) winning?

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