Wave optics


Confused over option 2 and 3 kindly see
And 2nd i am not getting all correct options so see this one too.

I used path difference due to reflection on mirror and direct path in second to get some relation but was not able to eliminate many variables , need simpler approach i guess.

Answer for question number 4 is option 2 and 3??

INCORRECT its not 2 and 4

I am telling the answer for the question in 2nd image the mirror one…
And i said it should be 2 and 3…

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Sorry my mistake
Thats correct how did u get it ? I tried but didnt got

Instead of considering phase difference from reflection etc etc…
You can consider 2 sources, one is the original source S and one will be its image in the mirror…
And treat this a normal YDSE experiment…
And fringe width will be the same as in YDSE, the only difference will be its slit/ source separation…
See the image attached to understand the difference…

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Initially take 2d and as per the question they shift the source by 0.6mm then take it as 2(d+0.6)… Like this you get 2 equations… And 2 variables… Lambda and d… Solve for d… You get the initial distance from A where source is kept… Now using any 1 equation find lambda…

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Thanks a lot , my method was very wrong
Try 1st one too

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